Prove that area(∆poq) + area(∆sor)= area (∆pos)+area(∆qor)=1/2 area (parallelogram pqrs)
Prove that area(∆poq) + area(∆sor)= area (∆pos)+area(∆qor)=1/2 area (parallelogram pqrs)
In the figure o is the centre of the circle AB is chord. in oab show that oab=oba