iIn triangle ABC,angle ACB=90 degree.seg CD perpendicular sode AB.and seg CE is angle bisector of Angle ACB.prove that :AD/BD=AE^2/BE^2
Question
iIn triangle ABC,angle ACB=90 degree.seg CD perpendicular sode AB.and seg CE is angle bisector of Angle ACB.prove that :AD/BD=AE^2/BE^2
In the figure area of parallelogram is80cm2 then area of triangle ABEis
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Answer
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Answer
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