Question

∫▒(x^2+2x+8)/(x-1)(x-2)

1-sin60°÷cos60°=tan60°-1÷tan60°+1

1-sin60°÷cos60°=tan60°-1÷tan60°+1

1-sin60°÷cos60°=tan60°-1÷tan60°+1

1-sin60°÷cos60°=tan60°-1÷tan60°+1

1-sin60°÷cos60°=tan60°-1÷tan60°+1

1-sin60°÷cos60°=tan60°-1÷tan60°+1

in triangle abc d and e are two points on bc of such that bd = ce and ad=ae shoe triangle abd is congruent to ace

I Want to learn

Sequence and series