gst

1 + 3 + 5 ….+ (2 n െ 1) = 2
n is true for n  N.

1ή2 + 2ή3 + ….+ n ( n + 1 ) = 3 1( )(nnn  )2 is true for n  N.

Is this method right 

how 5 pi by 4 came in 13 example of ncert application of ditivat

rcm applyed after 13-10-2017

stationary comes under which group

4.32 mixed reccuring decimal in the form of p/q

gstr 1 return

How pie6.5 came

find the equation of the locus of a point which moves such that abscissa and ordinate are always equal

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