Point definition by Mohi Chinese philosopher
finding the equation of a tangent and normal
finding the equation of a tangent
(1+y2)dx+2xy-dx=o
(1+y2)dx+2xy-dx=o solve
prove that tan^-1(2ab/a^2 -b^2) +tan^-1( 2xy/x^2 - y^2) =tan^-1(2pq/p^2 - q^2)
Solve dy/dx+ y tanx=secx
Sin(x+y)dy/dx=1
NCERT 9th class
pair of linear equations in two variables