MIDDLE TERM:
Show that middle term of the expansion of (1 X)^2n is 1.3.5....…....(2n-1)/n!×2^n.x^n.,where n is a positive integer.
Question
Sir, is this available input credit in company car repair and insurance.... Please explain
Maths
Oct. 16, 2018, 7:28 p.m.
Answer
Find the Radius of the circle whose centre is(3,2) and passes through (-5,6).
Maths
Oct. 16, 2018, 6:50 p.m.
Answer
Find the remainder, if the polynomial x⁴+x³ -3x²+3x+1 is divided by 3+2x