Question

Class 12 
7.9 2nd question there is a typing mistake instead of 3/2 it should be 5/2 and will obtaining 231 it should be 3×7×11

Chapter Dusk detailed question answer 

Kannada vibakati models ides

Find the value of k,such that 4x+5y=and kx+=9 have infinitely many solutions 

Why is the sky blue 

How many cubes of side 1 cm will make a cube of side 3 cm 

In the midpoint of the sides of a 4 jio and are joined in order prove that the area of the parallelogram has formed will be half of the area of the given for jio and you may wonder whether the 4G and has formed is always a parallelogram and if so why this question will be tackle and answer in the chapter on quadrilate

How to do gret in exam

Where did you upload new syllabus for 6 to 9 classes. 
I use this app from 3 years my brother also want to use that please upload it 
He has many doubt but no where has solution 
Thank you for read this and understand our problem 

Chapter 4 exercise 4.5 Q.no 1 – simplify the following rational expressions assuming that the expressions in the denominator are not equal to zero:

1. 
   

Quadrilateral exactly one pair of parallel sides

Find the sum and product of zero of polynomial.
    2 
3x.   -2x+5

• 
  

If 21y is multiple of 9 where y is a digit, what is the value of y

Derive the equation of the line in space passing through the point parallel to the vector in the vector form 

Question 8

Prove that

\[
2(\sin^6\theta+\cos^6\theta)-3(\sin^4\theta+\cos^4\theta)+1=0
\]

LHS:

\[
=2(\sin^6\theta+\cos^6\theta)
-3(\sin^4\theta+\cos^4\theta)+1
\]

We know,

\[
a^3+b^3=(a+b)^3-3ab(a+b)
\]

Taking \(a=\sin^2\theta,\ b=\cos^2\theta\),

\[
\sin^6\theta+\cos^6\theta
=(\sin^2\theta+\cos^2\theta)^3
-3\sin^2\theta\cos^2\theta
(\sin^2\theta+\cos^2\theta)
\]

Since

\[
\sin^2\theta+\cos^2\theta=1
\]

\[
\sin^6\theta+\cos^6\theta
=1-3\sin^2\theta\cos^2\theta
\]

Also,

\[
\sin^4\theta+\cos^4\theta
=(\sin^2\theta+\cos^2\theta)^2
-2\sin^2\theta\cos^2\theta
\]

\[
=1-2\sin^2\theta\cos^2\theta
\]

Substitute:

\[
=2(1-3\sin^2\theta\cos^2\theta)
-3(1-2\sin^2\theta\cos^2\theta)+1
\]

\[
=2-6\sin^2\theta\cos^2\theta
-3+6\sin^2\theta\cos^2\theta+1
\]

\[
=0
\]

Hence,

\[
\boxed{LHS=RHS=0}
\]

Hence proved. ✅

I want of 8th standard 

Ganita Manjari book se aap mujhe class ninth pt1 exam ke liye question de sakte hain paper mein kya aaega vaisa hi question chapter 1 and 2,3 please 

Y=√1-tanx÷1+tanx