how to solve this
In a right triangle ABC angle A = 90° and AD perpendicular to BC. Prove that AD^2 = BD×CD.
ABC is an isosceles triangle with AB = AC .D and E are two points at AB and AC such that AD =AE.Show that BE =CD
In a quadrilateral ABCD, with unequal sides if the diagonals AC and BD intersect at right angles , then what is relation between sides square??