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Ex 7.2
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Last updated at May 29, 2023 by Teachoo
Ex 7.2, 36 Integrate ((𝑥 + 1) (𝑥 + log𝑥 )^2)/𝑥 ∫1▒〖" " ((𝑥 + 1) (𝑥 + log𝑥 )^2)/𝑥〗 . 𝑑𝑥 Let 𝑥+log𝑥= 𝑡 Differentiating both sides 𝑤.𝑟.𝑡.𝑥 1+1/𝑥= 𝑑𝑡/𝑑𝑥 (𝑥 + 1)/𝑥= 𝑑𝑡/𝑑𝑥 " " 𝑑𝑥 = ((𝑥 )/(𝑥 + 1))𝑑𝑡 Now, our function becomes ∫1▒〖" " ((𝑥 + 1) (𝑥 + log𝑥 )^2)/𝑥〗 . 𝑑𝑥 Putting the value of 𝑥−𝑙𝑜𝑔𝑥=𝑡 & 𝑑𝑥=((𝑥 )/(𝑥 + 1))𝑑𝑡 = ∫1▒〖" " ((𝑥 + 1) (𝑡)^2)/𝑥〗 . (𝑥 )/((𝑥 + 1) ) . 𝑑𝑡 = ∫1▒〖" " 𝑡^2 〗. 𝑑𝑡" " = 𝑡^(2 + 1)/(2 + 1) +𝐶 = 𝑡^3/3 +𝐶 = 𝟏/𝟑 (𝒙+𝒍𝒐𝒈𝒙 )^𝟑+𝑪 (Using ∫1▒𝑥^𝑛 . 𝑑𝑥=𝑥^(𝑛+1)/(𝑛 +1)) (Using 𝑡=𝑥+𝑙𝑜𝑔𝑥)