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Ex 7.7, 1
β(4βπ₯2)
β«1βγβ(4βπ₯^2 ).ππ₯γ
=β«1βγβ((π)^πβπ^π ).π πγ
=1/2 π₯β((2)^2βπ₯^2 )+(2)^2/2 π ππ^(β1) π₯/2+πΆ
=π/π β(πβπ^π )+π πππ^(βπ) π/π+πͺ
It is of the form
β«1βγβ(π^2βπ₯^2 ). ππ₯=1/2 π₯β(π^2βπ₯^2 )+π^2/2 π ππ^(β1) π₯/π+πΆγ
Replacing a with 2, we get
Made by
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.
