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Ex 7.7
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Ex 7.7, 12 (Supplementary NCERT) Important Deleted for CBSE Board 2023 Exams
Ex 7.7, 13 (Supplementary NCERT) Deleted for CBSE Board 2023 Exams
Ex 7.7, 14 (Supplementary NCERT) Important Deleted for CBSE Board 2023 Exams
Last updated at March 16, 2023 by Teachoo
Ex 7.7, 6 - Chapter 7 Class 12 Integrals - NCERT Integrate √(x^2 + 4x − 5) ∫√(x^2 + 4x − 5) dx = ∫√(x^2 + 2.2.x − 5) dx Adding and subtracting 2^2 = ∫√(x^2 + 2.2.x +(2)^2 - (2)^2 − 5) dx = ∫√((x + 2)^2 - 9) dx = ∫√((x + 2)^2 - 3^2) dx It is of the form ∫√x^2 - a^2 dx = x/2 √x^2 - a^2 - a^2/2 log |x + √x^2 - a^2| + C Replacing x by x + 2. a by 3 = (𝑥+2)/2 √(𝑥^2+4𝑥+4−9)−9/2 𝑙𝑜𝑔|𝑥+2+√(𝑥^2+4𝑥+4−9)|+𝐶 =(𝒙 + 𝟐)/𝟐 √(𝒙^𝟐+𝟒𝒙−𝟓)−𝟗/𝟐 𝒍𝒐𝒈|𝒙+𝟐+√(𝒙^𝟐+𝟒𝒙−𝟓)|+𝑪