# Misc 1 - Chapter 7 Class 12 Integrals

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Misc 1 Integrate the function 1𝑥 − 𝑥3 We can write as : 1𝑥 − 𝑥3= 1 𝑥3 𝑥 − 𝑥3 𝑥3 = 1 𝑥3 𝑥 𝑥3 − 𝑥3 𝑥3 = 1 𝑥3 1 𝑥2 −1 Integrating w.r.t.x 1𝑥 − 𝑥3𝑑𝑥= 1 𝑥3 1 𝑥2 − 1 𝑑𝑥 Let t = 1 𝑥2−1 Differentiating with respect to 𝑥 𝑑𝑑𝑥 1 𝑥2−1= 𝑑𝑡𝑑𝑥 −2 𝑥3= 𝑑𝑡𝑑𝑥 𝑑𝑥= 𝑥3𝑑𝑡−2 Substituting value of t 1 𝑥3 1 𝑥2 −1𝑑𝑥= 1 𝑥3 𝑡 × 𝑥3𝑑𝑡−2 = 1−2 𝑑𝑡𝑡 = −1 2 𝑑𝑡𝑡 = −1 2𝑙𝑜𝑔 𝑡+𝐶 Putting back 𝑡= 1 𝑥2−1 = −1 2𝑙𝑜𝑔 1 𝑥2−1+𝐶 = −1 2𝑙𝑜𝑔 1 𝑥2− 𝑥2 𝑥2+𝐶 = −1 2𝑙𝑜𝑔 1 − 𝑥2 𝑥2+𝐶 = 12 log 1 − 𝑥2 𝑥2−1+𝐶 = 𝟏𝟐 log 𝒙𝟐𝟏 − 𝒙𝟐+𝑪

Miscellaneous

Misc 1
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Misc 2

Misc 3

Misc 4

Misc 5

Misc 6

Misc 7

Misc 8 Important

Misc 9

Misc 10

Misc 11

Misc 12

Misc 13

Misc 14

Misc 15

Misc 16

Misc 17

Misc 18 Important

Misc 19 Important

Misc 20 Important

Misc 21

Misc 22

Misc 23

Misc 24 Important

Misc 25

Misc 26

Misc 27

Misc 28

Misc 29

Misc 30 Important

Misc 31

Misc 32 Important

Misc 33

Misc 34

Misc 35

Misc 36

Misc 37

Misc 38

Misc 39

Misc 40

Misc 41 Important

Misc 42

Misc 43

Misc 44 Important

Integration Formula Sheet - Chapter 7 Class 12 Formulas Important

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.