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Misc 37 - Prove that definite integral sin3 x dx = 2/3 - Miscellaneous

Misc 37 - Chapter 7 Class 12 Integrals - Part 2
Misc 37 - Chapter 7 Class 12 Integrals - Part 3


Transcript

Misc 37 Prove that 0 2 sin 3 = 2 3 Solving L.H.S 0 2 sin 3 = 0 2 sin (sin 2 ) = 0 2 (1 2 ) = 0 2 0 2 sin 2 L.H.S = 1 2 = 1 1 3 = = R.H.S Hence, proved.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.