Misc 4 - Chapter 7 Class 12 Integrals
Last updated at August 5, 2026 by Teachoo
Miscellaneous
Misc 1
Important
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Chapter 7 Class 12 Integrals
Serial order wise
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Transcript
Misc 4 Integrate the function 1 𝑥2 𝑥4 + 1 34 1 𝑑𝑥 𝑥2 𝑥4 + 1 34 Taking 𝒙𝟒 common from denominator = 1 𝑑𝑥 𝑥2 (𝑥4) 34 1 + 1 𝑥4 34 = 𝑑𝑥 𝑥2 (𝑥3) 1 + 1 𝑥4 34 = 𝑑𝑥 𝑥5 1 + 1 𝑥4 34 Let t = 1 + 1 𝑥4 𝑑𝑡𝑑𝑥 = − 4 𝑥5 − 𝑑𝑡4 = 𝑑𝑥 𝑥5 Substituting value of x and dx = −14 𝑑𝑡 𝑡 34 = −14 𝑡 −34 𝑑𝑡 = −14 𝑡 −34 + 1 −34 + 1+ C = −14 𝑡 14 14+ C = − 𝑡 14+ C = − 𝟏+ 𝟏 𝒙𝟒 𝟏𝟒+ C
