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Misc 12 - Integrate x3 / root 1 - x8 - Chapter 7 NCERT - Miscellaneous

Misc 12 - Chapter 7 Class 12 Integrals - Part 2


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Misc 12 Integrate the function 3 1 8 3 1 8 = 3 1 4 2 Put 4 = Differentiating w.r.t. 4 3 = d = 4 3 Therefore, 3 1 4 2 = 3 1 2 4 3 = 1 4 1 2 = 1 4 sin 1 + Putting = 4 = +

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.