Misc 12 - Chapter 7 Class 12 Integrals

Last updated at April 16, 2024 by

Integ p1.jpg

Integ p2.jpg
 

Transcript

Misc 12 Integrate the function 3 1 8 3 1 8 = 3 1 4 2 Put 4 = Differentiating w.r.t. 4 3 = d = 4 3 Therefore, 3 1 4 2 = 3 1 2 4 3 = 1 4 1 2 = 1 4 sin 1 + Putting = 4 = +

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.