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Misc 12 - Integrate x3 / root 1 - x8 - Chapter 7 NCERT - Miscellaneous

Misc 12 - Chapter 7 Class 12 Integrals - Part 2


Transcript

Misc 12 Integrate the function 3 1 8 3 1 8 = 3 1 4 2 Put 4 = Differentiating w.r.t. 4 3 = d = 4 3 Therefore, 3 1 4 2 = 3 1 2 4 3 = 1 4 1 2 = 1 4 sin 1 + Putting = 4 = +

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.