
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 7.2, 1 Integrate the function: 2𝑥1+𝑥2 Let 1 + 𝑥2 = 𝑡 Differentiate 𝑤.𝑟.𝑡.𝑥 2𝑥= 𝑑𝑡𝑑𝑥 𝑑𝑥= 𝑑𝑡2𝑥 Thus, our equation becomes 2𝑥1 + 𝑥2 𝑑𝑥 = 2𝑥𝑡 . 𝑑𝑡2𝑥 = 𝑑𝑡𝑡 = log 𝑡+𝐶 Putting 𝑡 = 1 + 𝑥2 = log 1+ 𝑥2+𝐶 = log 1+ 𝑥2+𝐶
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