Ex 7.2, 20 - Chapter 7 Class 12 Integrals

Last updated at April 16, 2024 by

Ex 7.2, 20 - Integrate (e^2x - e^-2x) / (e^2x + e^-2x) - Ex 7.2

Ex 7.2, 20 - Chapter 7 Class 12 Integrals - Part 2

Go Ad-free

Transcript

Ex 7.2, 20 Integrate the function (๐‘’^2๐‘ฅ โˆ’ ๐‘’^(โˆ’2๐‘ฅ))/(๐‘’^2๐‘ฅ + ๐‘’^(โˆ’2๐‘ฅ) ) Let ๐‘’^2๐‘ฅ + ๐‘’^(โˆ’2๐‘ฅ)= ๐‘ก Differentiating both sides ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐‘’^2๐‘ฅ. ๐‘‘(2๐‘ฅ)/๐‘‘๐‘ฅ +๐‘’^(โˆ’2๐‘ฅ) ๐‘‘(โˆ’2๐‘ฅ)/๐‘‘๐‘ฅ= ๐‘‘๐‘ก/๐‘‘๐‘ฅ ใ€–2๐‘’ใ€—^2๐‘ฅโˆ’ใ€–2๐‘’ใ€—^(โˆ’2๐‘ฅ)= ๐‘‘๐‘ก/๐‘‘๐‘ฅ 2(๐‘’^2๐‘ฅโˆ’๐‘’^(โˆ’2๐‘ฅ) )=๐‘‘๐‘ก/๐‘‘๐‘ฅ " " ๐‘‘๐‘ฅ = ๐‘‘๐‘ก/2(๐‘’^2๐‘ฅโˆ’ ๐‘’^(โˆ’2๐‘ฅ) ) Integrating the function โˆซ1โ–’ใ€–" " (๐‘’^2๐‘ฅ โˆ’ ๐‘’^(โˆ’2๐‘ฅ))/(๐‘’^2๐‘ฅ + ๐‘’^(โˆ’2๐‘ฅ) )ใ€—. ๐‘‘๐‘ฅ Putting ๐‘’^2๐‘ฅ + ๐‘’^(โˆ’2๐‘ฅ)=๐‘ก & ๐‘‘๐‘ฅ=๐‘‘๐‘ก/2(๐‘’^2๐‘ฅโˆ’ ๐‘’^(โˆ’2๐‘ฅ) ) = โˆซ1โ–’ใ€–" " (๐‘’^2๐‘ฅ โˆ’ ๐‘’^(โˆ’2๐‘ฅ))/๐‘กใ€—. ๐‘‘๐‘ก/2(๐‘’^2๐‘ฅโˆ’ ๐‘’^(โˆ’2๐‘ฅ) ) = โˆซ1โ–’ใ€–" " 1/2๐‘กใ€—. ๐‘‘๐‘ก = 1/2 โˆซ1โ–’1/๐‘ก. ๐‘‘๐‘ก = 1/2 logโกใ€– |๐‘ก|ใ€—+๐ถ = 1/2 logโกใ€– |๐‘’^2๐‘ฅ + ๐‘’^(โˆ’2๐‘ฅ) |ใ€—+๐ถ = ๐Ÿ/๐Ÿ ๐’๐’๐’ˆโกใ€– (๐’†^๐Ÿ๐’™ + ๐’†^(โˆ’๐Ÿ๐’™) )ใ€—+๐‘ช (Using โˆซ1โ–’1/๐‘ฅ. ๐‘‘๐‘ฅ=๐‘™๐‘œ๐‘”โก|๐‘ฅ| ) (Using ๐‘ก=๐‘’^2๐‘ฅ + ๐‘’^(โˆ’2๐‘ฅ)) (โˆด ๐‘’^2๐‘ฅ+๐‘’^(โˆ’2๐‘ฅ)>0 )

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo