Ex 7.2, 20 - Chapter 7 Class 12 Integrals
Last updated at July 11, 2018 by Teachoo
Transcript
Ex 7.2, 20 (π^2π₯ β π^(β2π₯))/(π^2π₯ + π^(β2π₯) ) Step 1: Let π^2π₯ + π^(β2π₯)= π‘ Differentiating both sides π€.π.π‘.π₯ π^2π₯. π(2π₯)/ππ₯ +π^(β2π₯) π(β2π₯)/ππ₯= ππ‘/ππ₯ γ2πγ^2π₯βγ2πγ^(β2π₯)= ππ‘/ππ₯ 2(π^2π₯βπ^(β2π₯) )=ππ‘/ππ₯ " " ππ₯ = ππ‘/2(π^2π₯β π^(β2π₯) ) Step 2: Integrating the function β«1βγ" " (π^2π₯ β π^(β2π₯))/(π^2π₯ + π^(β2π₯) )γ. ππ₯ Putting π^2π₯ + π^(β2π₯)=π‘ & ππ₯=ππ‘/2(π^2π₯β π^(β2π₯) ) = β«1βγ" " (π^2π₯ β π^(β2π₯))/π‘γ. ππ‘/2(π^2π₯β π^(β2π₯) ) = β«1βγ" " 1/2π‘γ. ππ‘ = 1/2 β«1β1/π‘. ππ‘ = 1/2 logβ‘γ |π‘|γ+πΆ = 1/2 logβ‘γ |π^2π₯ + π^(β2π₯) |γ+πΆ = π/π πππβ‘γ (π^ππ + π^(βππ) )γ+πͺ
Ex 7.2
Ex 7.2, 1
Ex 7.2, 2
Ex 7.2, 3
Ex 7.2, 4
Ex 7.2, 5
Ex 7.2, 6
Ex 7.2, 7
Ex 7.2, 8
Ex 7.2, 9
Ex 7.2, 10
Ex 7.2, 11
Ex 7.2, 12
Ex 7.2, 13
Ex 7.2, 14
Ex 7.2, 15
Ex 7.2, 16
Ex 7.2, 17
Ex 7.2, 18
Ex 7.2, 19
Ex 7.2, 20 Important You are here
Ex 7.2, 21
Ex 7.2, 22
Ex 7.2, 23
Ex 7.2, 24
Ex 7.2, 25
Ex 7.2, 26 Important
Ex 7.2, 27
Ex 7.2, 28
Ex 7.2, 29
Ex 7.2, 30
Ex 7.2, 31
Ex 7.2, 32
Ex 7.2, 33
Ex 7.2, 34
Ex 7.2, 35 Important
Ex 7.2, 36 Important
Ex 7.2, 37
Ex 7.2, 38
Ex 7.2, 39
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.