Ex 7.2, 29
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 7.2, 29 cot𝑥 logsin𝑥 Step 1: Let logsin𝑥=𝑡 Differentiating both sides 𝑤.𝑟.𝑡.𝑥 1 sin𝑥 . 𝑑𝑑𝑥 sin 𝑥= 𝑑𝑡𝑑𝑥 1 sin𝑥 . co𝑠𝑥= 𝑑𝑡𝑑𝑥 cot𝑥= 𝑑𝑡𝑑𝑥 𝑑𝑥= 𝑑𝑡 cot𝑥 Step 2: Integrating the function cot𝑥 logsin𝑥. 𝑑𝑥 putting 𝑙𝑜𝑔 𝑠𝑖𝑛𝑥=𝑡 & 𝑑𝑥= 𝑑𝑡 cot𝑥 = cot𝑥. 𝑡 . 𝑑𝑡 cot𝑥 = 𝑡. 𝑑𝑡 = 𝑡1 + 11 + 1 +𝐶 = 𝑡22 +𝐶 = 𝟏𝟐 𝐥𝐨𝐠 𝐬𝐢𝐧𝒙𝟐+𝑪
Ex 7.2
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.