∫e^x  (cos⁑x - sin⁑x) dx is equal to

(A) e^x  cos⁑x + C  

(B) e^x  sin⁑x + C

(C) -e^x  cos⁑x + C    

(D) -e^x  sin⁑x + C

This question is similar to Ex 7.6, 16 - Chapter 7 Class 12 - Integrals

Slide1.JPG

  1. Chapter 7 Class 12 Integrals (Term 2)
  2. Serial order wise

Transcript

Question 1 ∫1▒𝑒^π‘₯ (cos⁑π‘₯ βˆ’sin⁑π‘₯ ) 𝑑π‘₯ is equal to 𝑒^π‘₯ cos⁑π‘₯+𝐢 (B) 𝑒^π‘₯ sin⁑π‘₯+𝐢 (C) γ€–βˆ’π‘’γ€—^π‘₯ cos⁑π‘₯+𝐢 (D)γ€–βˆ’π‘’γ€—^π‘₯ sin⁑π‘₯+𝐢 ∫1▒〖𝑒^π‘₯ (cos⁑π‘₯βˆ’sin⁑π‘₯)γ€— 𝑑π‘₯ Putting 𝒇(𝒙)=𝒄𝒐𝒔 𝒙" " ∴ 𝒇^β€² (𝒙)=γ€–βˆ’π‘ π‘–π‘›γ€—β‘π‘₯ Thus, ∫1▒〖𝑒^π‘₯ (cos⁑π‘₯βˆ’sin⁑π‘₯)γ€— 𝑑π‘₯=𝒆^𝒙 𝒄𝒐𝒔 𝒙+π‘ͺ So, the correct answer is (a)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.