If x= โˆซ 0^y dt/โˆš(1 + 9t^2) and (d^2 y) / (dx^2 ) = ay, then a is equal to

(A) 3ย 

(B) 6ย 

(C) 9ย 

(D) 1

If ๐‘ฅ = โˆซ ๐‘‘๐‘ก /โˆš(1 + 9๐‘ก^2) from 0 to y & (๐‘‘^2 ๐‘ฆ)/(๐‘‘๐‘ฅ^2 ) = ๐‘Ž๐‘ฆ - NCERT Exemplar MCQ

part 2 - Question 6 - NCERT Exemplar MCQ - Serial order wise - Chapter 7 Class 12 Integrals
part 3 - Question 6 - NCERT Exemplar MCQ - Serial order wise - Chapter 7 Class 12 Integrals

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Transcript

Question 6 If ๐‘ฅ= โˆซ1_0^๐‘ฆโ–’ใ€– ๐‘‘๐‘ก/โˆš(1 + 9๐‘ก^2 )ใ€— and (๐‘‘^2 ๐‘ฆ)/(๐‘‘๐‘ฅ^2 )=๐‘Ž๐‘ฆ, then ๐‘Ž is equal to 3 (B) 6 (C) 9 (D) 1 Since ๐‘ฅ= โˆซ1_0^๐‘ฆโ–’ใ€– ๐‘‘๐‘ก/โˆš(1 + 9๐‘ก^2 )ใ€— Changing variable from t to y ๐‘ฅ= โˆซ1_0^๐‘ฆโ–’ใ€– ๐‘‘๐‘ฆ/โˆš(1 + 9๐‘ฆ^2 )ใ€— It means x is a function of y So, we can write ๐’…๐’™/๐’…๐’š=๐Ÿ/โˆš(๐Ÿ + ๐Ÿ—๐’š^๐Ÿ ) And, ๐๐’š/๐๐ฑ=โˆš(1 + 9๐‘ฆ^2 ) Differentiating again w.r.t x (๐^๐Ÿ ๐’š)/(๐๐ฑ^๐Ÿ )=๐Ÿ/(๐Ÿโˆš(1 + 9๐‘ฆ^2 )) ร—๐’…(๐Ÿ—๐’š^๐Ÿ )/๐’…๐’™ (d^2 ๐‘ฆ)/(dx^2 )=1/(2โˆš(1 + 9๐‘ฆ^2 )) ร— 9 ร— 2๐‘ฆ ร—๐’…๐’š/๐’…๐’™ Putting value of ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ (๐^๐Ÿ ๐’š)/(๐๐ฑ^๐Ÿ )=๐Ÿ/(๐Ÿโˆš(1 + 9๐‘ฆ^2 )) ร— ๐Ÿ— ร— ๐Ÿ๐’š ร—โˆš(1 + 9๐‘ฆ^2 ) (๐^๐Ÿ ๐’š)/(๐๐ฑ^๐Ÿ )=๐Ÿ—๐’š Thus, a = 9 So, the correct answer is (c)

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