# Ex 7.4, 1 - Chapter 7 Class 12 Integrals (Term 2)

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 7.4, 1 3 𝑥2 𝑥6 + 1 Let 𝑥3=𝑡 Diff both sides w.r.t.x 3 𝑥2= 𝑑𝑡𝑑𝑥 𝑑𝑥= 𝑑𝑡3 𝑥2 Step :- 2 Integrating the function 𝑤.𝑟.𝑡.𝑥 3 𝑥2 𝑥6 + 1 𝑑𝑥 = 3 𝑥2 𝑥32 + 1 𝑑𝑥 Putting the value of 𝑥3 and 𝑑𝑥= 𝑑𝑡3 𝑥2 = 3 𝑥2 𝑡2 + 1 . 𝑑𝑡3 𝑥2 = 𝑑𝑡 𝑡2 + 1 = 𝑑𝑡 𝑡2 + 12 = 11 tan−1 𝑡1 +𝐶 = tan−1 𝑡+𝐶 = 𝒕𝒂𝒏−𝟏 𝒙𝟑+𝑪

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.