Ex 7.4, 16 - Integrate 4x + 1 / root 2x2 + x - 3 - Ex 7.4

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  1. Chapter 7 Class 12 Integrals
  2. Serial order wise
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Ex 7.4, 16 (4 + 1)/ (2 ^2 + 3) Let 2 ^2+ 3= Diff both sides w.r.t. x 4 +1+0= / = /(4 + 1) Now, 1 (4 + 1)/ (2 ^2 + 3) Put the values of (2 ^2+ 3)= and = /(4 + 1) = 1 (4 + 1)/ /(4 + 1) = 1 1/ = 1 ^(( 1)/2) = ^(( 1)/2 + 1)/(( 1)/2 + 1) + = ^(1/2)/(1/2) + =2 ^(1/2) + =2 + = ( ^ + )+

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