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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


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Ex 7.1, 1 Find anti derivative of sin 2x We know that γ€– (cos⁑〖 π‘₯γ€— )γ€—^β€²=γ€–βˆ’sin〗⁑π‘₯ γ€– (πœπ¨π¬β‘γ€– πŸπ’™γ€— )γ€—^β€²=γ€–βˆ’π¬π’π§γ€—β‘πŸπ’™ Γ— 𝟐 (βˆ’1)/( 2) (cos⁑〖 2π‘₯γ€— )^β€²=sin⁑2π‘₯ sin⁑2π‘₯=(βˆ’1)/( 2) (cos⁑2π‘₯ )^β€² sin⁑2π‘₯=((βˆ’1)/( 2) cos⁑2π‘₯ )^β€² ∴ Anti derivate of 𝑠𝑖𝑛⁑2π‘₯=(βˆ’πŸ)/𝟐 πœπ¨π¬β‘πŸπ’™

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.