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Ex 7.1, 1 Find anti derivative of sin 2x We know that γ€– (cos⁑〖 π‘₯γ€— )γ€—^β€²=γ€–βˆ’sin〗⁑π‘₯ γ€– (πœπ¨π¬β‘γ€– πŸπ’™γ€— )γ€—^β€²=γ€–βˆ’π¬π’π§γ€—β‘πŸπ’™ Γ— 𝟐 (βˆ’1)/( 2) (cos⁑〖 2π‘₯γ€— )^β€²=sin⁑2π‘₯ sin⁑2π‘₯=(βˆ’1)/( 2) (cos⁑2π‘₯ )^β€² sin⁑2π‘₯=((βˆ’1)/( 2) cos⁑2π‘₯ )^β€² ∴ Anti derivate of 𝑠𝑖𝑛⁑2π‘₯=(βˆ’πŸ)/𝟐 πœπ¨π¬β‘πŸπ’™

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.