Ex 7.1, 1 Find anti derivative of sin 2x We know that 〖 (cos⁡〖 𝑥〗 )〗^′=〖−sin〗⁡𝑥 〖 (𝐜𝐨𝐬⁡〖 𝟐𝒙〗 )〗^′=〖−𝐬𝐢𝐧〗⁡𝟐𝒙 × 𝟐 (−1)/( 2) (cos⁡〖 2𝑥〗 )^′=sin⁡2𝑥 sin⁡2𝑥=(−1)/( 2) (cos⁡2𝑥 )^′ sin⁡2𝑥=((−1)/( 2) cos⁡2𝑥 )^′ ∴ Anti derivate of 𝑠𝑖𝑛⁡2𝑥=(−𝟏)/𝟐 𝐜𝐨𝐬⁡𝟐𝒙

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.

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