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Ex 7.8
Last updated at April 16, 2024 by Teachoo
Ex 7.8, 1 ∫_(−1)^1▒(𝑥+1)𝑑𝑥 Let F(𝒙)=∫1▒(𝑥+1)𝑑𝑥 =𝑥^(1+1)/(1+1)+𝑥 =𝒙^𝟐/𝟐+𝒙 Hence F(𝑥)=𝑥^2/2+𝑥 ∫_(−𝟏)^𝟏▒(𝒙+𝟏)𝒅𝒙 =𝑭(𝟏)−𝑭(−𝟏) =((1)^2/2+1)−((−1)^2/2+(−1)) =(1/2+1)−(1/2−1) =1/2+1−1/2+1 = 1/2−1/2+1+1 = 2