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Ex 7.9, 4 - Direct Integrate sin 2x dx from 0 to pi/4 - Ex 7.9

Ex 7.9, 4 - Chapter 7 Class 12 Integrals - Part 2


Transcript

Ex 7.9, 4 ∫_0^(πœ‹/4)β–’sin⁑2π‘₯𝑑π‘₯ Let F(π‘₯)=∫1▒〖𝑠𝑖𝑛 2π‘₯ 𝑑π‘₯γ€— =1/2 (βˆ’π‘π‘œπ‘  2π‘₯) =(βˆ’1)/( 2) π‘π‘œπ‘  2π‘₯ Hence, F(π‘₯)=(βˆ’1)/( 2) π‘π‘œπ‘  2π‘₯ Now, ∫_0^(πœ‹/4)▒〖𝑠𝑖𝑛2π‘₯ 𝑑π‘₯γ€—=𝐹(πœ‹/4)βˆ’πΉ(0) =(βˆ’1)/( 2) π‘π‘œπ‘ (2 Γ— πœ‹/4)βˆ’((βˆ’1)/( 2) π‘π‘œπ‘ (2 Γ—0)) =(βˆ’1)/( 2) π‘π‘œπ‘  πœ‹/2+1/2 π‘π‘œπ‘  0 =(βˆ’1)/( 2) Γ—0+1/2 Γ—1 = 𝟏/𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.