Ex 7.9, 13 - Chapter 7 Class 12 Integrals (Term 2)
Last updated at May 29, 2018 by
Transcript
Ex7.9, 13 2 3 2+1 Step 1 :- Let F = 2 + 1 Let 2 + 1= Differentiating w.r.t. 2 +1 = 2 = d = 2 Putting Values of 2 +1= & = 2 2 + 1 = 2 = 1 2 = 1 2 = 1 2 2 +1 Hence F = 1 2 2 +1 Step 2 :- 2 3 2 +1 = 3 2 = 1 2 3 2 +1 1 2 2 2 +1 = 1 2 log 10 1 2 5 = 1 2 log 10 log 5 = 1 2 10 5 =
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