Ex 7.9, 3 - Chapter 7 Class 12 Integrals (Term 2)
Last updated at May 29, 2018 by Teachoo
Transcript
Ex7.9, 3 12(4𝑥3−5𝑥2+6𝑥+9) 𝑑𝑥 Step 1 :- F 𝑥= 4 𝑥3−5 𝑥2+6𝑥+9𝑑𝑥 = 4 𝑥3+13+1− 5 𝑥2+12+1+ 6 𝑥1+11+1+9𝑥 = 4 𝑥44− 5 𝑥33+ 6 𝑥22+9𝑥 = 𝑥4− 53 𝑥3+ 3𝑥2+9𝑥 Hence f(x) =𝑥4− 3 𝑥33+3 𝑥2+9𝑥 Step 2 :- 12 4 𝑥2−9 𝑥2+6𝑥+9𝑑𝑥 =𝐹 2−𝐹 1 = 24− 53 23+3 22+9 2− 14− 53 × 13+3 × 12+9 ×1 =16− 53 ×8+3 ×4+9 ×2−1+ 53−3−9 =16− 403 +12+18−1+ 53−3−9 =33− 353 = 3 33 − 353 = 𝟔𝟒𝟑
Ex 7.9
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Ex 7.9, 3 You are here
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Ex 7.9, 21 (MCQ) Important
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