Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Ex 7.8, 2 ∫_2^3▒〖1/𝑥 𝑑𝑥〗 F(𝑥)=∫1▒〖1/𝑥 𝑑𝑥〗 =𝒍𝒐𝒈|𝒙| Hence F(𝑥)=𝑙𝑜𝑔|𝑥| ∫1_𝟐^𝟑▒𝟏/𝒙 𝒅𝒙=𝐹(3)−𝐹(2) =𝑙𝑜𝑔|3|−𝑙𝑜𝑔|2| =𝑙𝑜𝑔|3/2| =𝐥𝐨𝐠⁡ 𝟑/𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.