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Ex 7.8

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Last updated at June 13, 2023 by Teachoo

Ex 7.8, 7 β«_0^(π/4)βγπ‘ππ π₯γβ‘ππ₯ Step 1 :- F(π₯)=β«1βγtanβ‘π₯ ππ₯γ =πππ|π ππ π₯| Hence F(π₯)=πππ|π ππ π₯| Step 2 :- β«_0^(π/4)βtanβ‘γπ₯ ππ₯=πΉ(π/4)βπΉ(0)γ =πππ|π ππ (π/4)|βπππ|π ππ(0)| =πππ|β2|βπππ|1| =logβ‘β2β0 =logβ‘β2 = logβ‘γ2^(1/2) γ =π/π πππβ‘π