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Ex 7.8, 7 - Chapter 7 Class 12 Integrals

Last updated at June 13, 2023 by

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Ex 7.8, 7 ∫_0^(πœ‹/4)β–’γ€–π‘‘π‘Žπ‘› π‘₯〗⁑𝑑π‘₯ Step 1 :- F(π‘₯)=∫1β–’γ€–tan⁑π‘₯ 𝑑π‘₯γ€— =π‘™π‘œπ‘”|𝑠𝑒𝑐 π‘₯| Hence F(π‘₯)=π‘™π‘œπ‘”|𝑠𝑒𝑐 π‘₯| Step 2 :- ∫_0^(πœ‹/4)β–’tan⁑〖π‘₯ 𝑑π‘₯=𝐹(πœ‹/4)βˆ’πΉ(0)γ€— =π‘™π‘œπ‘”|𝑠𝑒𝑐 (πœ‹/4)|βˆ’π‘™π‘œπ‘”|𝑠𝑒𝑐(0)| =π‘™π‘œπ‘”|√2|βˆ’π‘™π‘œπ‘”|1| =log⁑√2βˆ’0 =log⁑√2 = log⁑〖2^(1/2) γ€— =𝟏/𝟐 π’π’π’ˆβ‘πŸ

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.