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Slide18.JPG


Transcript

Ex 7.8, 9 โˆซ_0^1โ–’๐‘‘๐‘ฅ/โˆš(1โˆ’๐‘ฅ2) Step 1 :- Let F(๐‘ฅ)=โˆซ1โ–’๐‘‘๐‘ฅ/โˆš(1 โˆ’ ๐‘ฅ^2 ) =โˆซ1โ–’๐‘‘๐‘ฅ/โˆš(1^2 โˆ’ ๐‘ฅ^2 ) =sin^(โˆ’1)โกใ€–๐‘ฅ/1ใ€— =๐‘ ๐‘–๐‘›^(โˆ’1) ๐‘ฅ Hence F(๐‘ฅ)=๐‘ ๐‘–๐‘›^(โˆ’1) ๐‘ฅ Step 2 :- โˆซ_0^1โ–’ใ€–๐‘‘๐‘ฅ/โˆš(1 โˆ’ ๐‘ฅ^2 )=๐น(1)โˆ’๐น(0) ใ€— =๐‘ ๐‘–๐‘›^(โˆ’1) (1)โˆ’๐‘ ๐‘–๐‘›^(โˆ’1) (0) =๐œ‹/2โˆ’0 =๐œ‹/2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.