Ex 7.2, 13 - Class 12
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 7.2, 13 Integrate the function: 𝑥2 2 + 3 𝑥33 Step 1: Let 2+3𝑥3=𝑡 Differentiating both sides 𝑤.𝑟.𝑡.𝑥 0+3.3 𝑥3−1= 𝑑𝑡𝑑𝑥 9 𝑥2= 𝑑𝑡𝑑𝑥 𝑑𝑥 = 𝑑𝑡9 𝑥2 Step 2: Integrating the function 𝑥2 2 + 3 𝑥33 . 𝑑𝑥 putting 2 + 3 𝑥3=𝑡 & 𝑑𝑥= 𝑑𝑡9 𝑥2 = 𝑥2 𝑡3 . 𝑑𝑥 = 𝑥2 𝑡3 . 𝑑𝑡9 𝑥2 = 19 𝑑𝑡 𝑡3 = 19 𝑡−3.𝑑𝑡 = 19 𝑡−3 + 1 −3 +1 + 𝐶 = 19 𝑡−2 −2 + 𝐶 = − 118 𝑡−2 + 𝐶 = − 118 𝑡2 + 𝐶 = − 𝟏𝟏𝟖 𝟐 + 𝟑 𝒙𝟑𝟐 + 𝑪
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.