# Misc 16 - Chapter 7 Class 12 Integrals (Term 2)

Last updated at May 29, 2018 by

Last updated at May 29, 2018 by

Transcript

Misc 16 Integrate the function 3 log 4 +1 1 Hence we can write 3 log 4 +1 1 = log 3 4 +1 1 = 3 4 +1 1 Integrating . . . 3 log 4 +1 1 = 3 4 +1 1 Put t = x 4 +1 Differentiating . . . = 4 3 4 3 = Therefore we can write 3 4 +1 1 = 3 1 4 3 = 1 4 1 = 1 4 = 1 4 log + Putting t = 4 +1 = 1 4 log 4 +1 +C = log ( + ) +

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Misc 16 You are here

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Integration Formula Sheet - Chapter 7 Class 12 Formulas Important

Chapter 7 Class 12 Integrals (Term 2)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.