Ex 7.7, 8 - Chapter 7 Class 12 Integrals (Term 2)
Last updated at Dec. 20, 2019 by Teachoo
Transcript
Ex 7.7, 8 β(π₯2+3π₯) β«1βγβ(π₯^2+3π₯) ππ₯γ =β«1βγβ(π₯^2+2(3/2)(π₯) ) ππ₯γ =β«1βγβ(π₯^2+2(3/2)(π₯)+(3/2)^2β(3/2)^2 ) ππ₯γ =β«1βγβ((π₯+3/2)^2β(3/2)^2 ) ππ₯γ It is of the form β«1βγβ(π₯^2βπ^2 ) ππ₯=π₯/2 β(π₯^2βπ^2 )βπ^2/2 πππ|π₯+β(π₯^2βπ^2 )|+πΆγ β΄ Replacing π₯ by π₯+3/2 and a by 3/2 , we get =(π₯ + 3/2)/2 β((π₯+3/2)^2β(3/2)^2 )β|π₯+3/2+β((π₯+π₯/2)^2β(3/2)^2 )|+πΆ =(2π₯ + 3)/4 β((π₯+3/2)^2β9/4) β 9/8 πππ|π₯+3/2 β((π₯+3/2)^2β9/4)|+πΆ =(2π₯ + 3)/4 β(π₯^2+9/4+2(π₯)(3/2)β9/4) β 9/8 πππ|π₯+3/2+β(π₯^2+9/4+2 (π₯)(3/2)β9/4)|+πΆ =(2π₯ + 3)/4 β(π₯^2+2π₯(3/2) )β 9/8 πππ|π₯+3/2+β(π₯^2+2π₯(3/2) )|+πΆ =(ππ + π)/π β(π^π+ππ)β π/π πππ|π+π/π+β(π^π+ππ)|+πͺ
Ex 7.7
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Ex 7.7, 8 Important You are here
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Ex 7.7, 12 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams
Ex 7.7, 13 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams
Ex 7.7, 14 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.