Ā  Ex 6.3, 3 (ii) - For g(x) = x^3 - 3x, find local maxima and minima - Ex 6.3

part 2 - Ex 6.3, 3 (ii) - Ex 6.3 - Serial order wise - Chapter 6 Class 12 Application of Derivatives
part 3 - Ex 6.3, 3 (ii) - Ex 6.3 - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Ex 6.3, 3 Find the local maxima and local minima, if any, of the following functions. Find also the local maximum and the local minimum values, as the case may be: (ii) š‘”(š‘„)=š‘„3 –3š‘„š‘”(š‘„)=š‘„3 –3š‘„ Finding g’(š’™) g’(š‘„)=š‘‘(š‘„^3 āˆ’ 3š‘„)/š‘‘š‘„ g’(š‘„)=3š‘„^2āˆ’3 Putting g’(š’™)=šŸŽ 3š‘„^2āˆ’3=0 3š‘„^2=3 š‘„^2=3/3 š‘„^2=1 š‘„=±1 So, x = 1 & x = –1 Finding g’’(š’™) g’(š‘„)=3š‘„^2āˆ’3 g’’(š‘„)=š‘‘(3š‘„^2āˆ’3)/š‘‘š‘„ = 6š‘„āˆ’0 = 6š‘„ Putting š’™=šŸ in g’’(x) g’’(1)=6(1)= 6 > 0 Thus, g’’(š‘„)>0 when š‘„=1 ⇒ š‘„=1 is point of local minima & g(š‘„) is minimum at š‘„=1 Local minimum value g(š‘„)=š‘„^3āˆ’3š‘„ g(1)=(1)^3āˆ’3(1) =1āˆ’3 =āˆ’šŸ Putting š’™=āˆ’šŸ in g’’(x) g’’(āˆ’1)=6(āˆ’1)= –6 < 0 Thus, g’’(š‘„)<0 when š‘„=āˆ’1 ⇒ š‘„=āˆ’1 is point of local maxima & g(š‘„) is maximum at š‘„=āˆ’1 Local minimum value g(š‘„)=š‘„^3āˆ’3š‘„ g(āˆ’1)=(āˆ’1)^3āˆ’3(āˆ’1) =āˆ’1+3 =šŸ

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