Ex 6.3, 2 (i) - Chapter 6 Class 12 Application of Derivatives

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Ex 6.3, 2 Find the maximum and minimum values, if any, of the following functions given by (i) 𝑓 (𝑥)=|𝑥 + 2| –1 𝑓 (𝑥)=|𝑥 + 2| –1 Minimum value of |𝑥 + 2|=0 Minimum value of f(𝑥)= minimum value of |𝑥 + 2| –1 =0−1 =−1 Hence minimum value of f(𝒙)=−𝟏 And there is no maximum value of f(x)

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