Ex 6.5, 2 - Find max and min values (i) f(x) = |x + 2| - 1

 

 

  1. Chapter 6 Class 12 Application of Derivatives (Term 1)
  2. Serial order wise

Transcript

Ex 6.5, 2 Find the maximum and minimum values, if any, of the following functions given by (i) 𝑓 (π‘₯)=|π‘₯ + 2| –1 𝑓 (π‘₯)=|π‘₯ + 2| –1 Minimum value of |π‘₯ + 2|=0 Minimum value of f(π‘₯)= minimum value of |π‘₯ + 2| –1 =0βˆ’1 =βˆ’1 Hence minimum value of f(𝒙)=βˆ’πŸ And there is no maximum value of f(x)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.