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Ex 6.5, 2 - Find max and min values (i) f(x) = |x + 2| - 1

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Ex 6.5, 2 Find the maximum and minimum values, if any, of the following functions given by (i) 𝑓 (π‘₯)=|π‘₯ + 2| –1 𝑓 (π‘₯)=|π‘₯ + 2| –1 Minimum value of |π‘₯ + 2|=0 Minimum value of f(π‘₯)= minimum value of |π‘₯ + 2| –1 =0βˆ’1 =βˆ’1 Hence minimum value of f(𝒙)=βˆ’πŸ And there is no maximum value of f(x)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.