Ex 6.5, 2 (i) - Chapter 6 Class 12 Application of Derivatives (Term 1)
Last updated at Aug. 19, 2021 by Teachoo
Transcript
Ex 6.5, 2 Find the maximum and minimum values, if any, of the following functions given by (i) π (π₯)=|π₯ + 2| β1 π (π₯)=|π₯ + 2| β1 Minimum value of |π₯ + 2|=0 Minimum value of f(π₯)= minimum value of |π₯ + 2| β1 =0β1 =β1 Hence minimum value of f(π)=βπ And there is no maximum value of f(x)
Ex 6.5
Ex 6.5, 1 (i)
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Ex 6.5, 1 (ii)
Ex 6.5, 1 (iii) Important
Ex 6.5, 1 (iv)
Ex 6.5, 2 (i) You are here
Ex 6.5, 2 (ii) Important
Ex 6.5, 2 (iii)
Ex 6.5, 2 (iv) Important
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Ex 6.5, 3 (v)
Ex 6.5, 3 (vi)
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Ex 6.5, 3 (viii)
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Ex 6.5, 5 (iv)
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Ex 6.5, 27 (MCQ)
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