Ex 6.5, 4 (iii) - Chapter 6 Class 12 Application of Derivatives (Term 1)

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Ex 6.5,4 - Chapter 6 Class 12 Application of Derivatives - Part 3

Ex 6.5,4 - Chapter 6 Class 12 Application of Derivatives - Part 4

Transcript

Ex 6.5, 4 Prove that the following functions do not have maxima or minima: (iii) ℎ(𝑥)= 𝑥^3+𝑥^2+𝑥+1Given h (x) = x3 + x2 + x + 1 Finding maxima or minima ℎ’ (𝑥) = 3𝑥^2+2𝑥+1 Putting ℎ’ (𝑥)= 0 3𝑥^2+2𝑥+1=0 For ax2 + bx + c = 0 x = (−𝑏 ± √(𝑏^2 − 4𝑎𝑐))/2𝑎 Here 𝑎 = 3, b = 2, & c = 1 x = (− 2 ± √(4 − 4(3)(1)))/6 x = (− 2 ± √(4 − 12))/6 x = (−2 ± √(− 8))/6 x = (− 2 ± 2√(− 2))/6 x = (−𝟏 ± √(− 𝟐))/𝟑 Since root has minus sign, x has no real value ∴ h (x) does not have a maxima of minima

Ex 6.5

Ex 6.5, 4 (iii) You are here

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Chapter 6 Class 12 Application of Derivatives (Term 1)

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