# Ex 6.5,6 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 6.5,6 Find the maximum profit that a company can make, if the profit function is given by ๐(๐ฅ) = 41 โ 72๐ฅ โ 18๐ฅ2 The profit function is given by p(x) = 41 โ 72x โ 18x2 pโ(x) = โ72 โ 36 x Putting pโ (x) = 0 โ72 โ 36x = 0 โ36x = 72 ๐ฅ =๏ทโ72๏ทฎ36๏ทฏ= โ2 Now, Pโ(x) = โ36 Since Pโ (x) < 0 ๐ฅ=โ2 is the maxima โด Maximum profit = p(โ2) p(x) = 41 โ 72x โ 18x2 ๐(โ2)=41โ72 ๏ทโ2๏ทฏโ18 ๏ท๏ทโ2๏ทฏ๏ทฎ2๏ทฏ =41+144โ18 ๏ท4๏ทฏ =41+144โ72 =113 Hence, the maximum profit is 113 unit.

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Chapter 6 Class 12 Application of Derivatives

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.