# Ex 6.5,6 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 6.5,6 Find the maximum profit that a company can make, if the profit function is given by ๐(๐ฅ) = 41 โ 72๐ฅ โ 18๐ฅ2 The profit function is given by p(x) = 41 โ 72x โ 18x2 pโ(x) = โ72 โ 36 x Putting pโ (x) = 0 โ72 โ 36x = 0 โ36x = 72 ๐ฅ =๏ทโ72๏ทฎ36๏ทฏ= โ2 Now, Pโ(x) = โ36 Since Pโ (x) < 0 ๐ฅ=โ2 is the maxima โด Maximum profit = p(โ2) p(x) = 41 โ 72x โ 18x2 ๐(โ2)=41โ72 ๏ทโ2๏ทฏโ18 ๏ท๏ทโ2๏ทฏ๏ทฎ2๏ทฏ =41+144โ18 ๏ท4๏ทฏ =41+144โ72 =113 Hence, the maximum profit is 113 unit.

Ex 6.5

Ex 6.5,1
Important

Ex 6.5,2 Important

Ex 6.5,3

Ex 6.5,4

Ex 6.5,5 Important

Ex 6.5,6 You are here

Ex 6.5,7 Important

Ex 6.5,8

Ex 6.5,9 Important

Ex 6.5,10

Ex 6.5,11 Important

Ex 6.5,12 Important

Ex 6.5,13

Ex 6.5,14 Important

Ex 6.5,15 Important

Ex 6.5,16

Ex 6.5,17

Ex 6.5,18 Important

Ex 6.5,19 Important

Ex 6.5, 20 Important

Ex 6.5,21

Ex 6.5,22 Important

Ex 6.5,23 Important

Ex 6.5,24 Important

Ex 6.5,25 Important

Ex 6.5,26 Important

Ex 6.5, 27

Ex 6.5,28 Important

Ex 6.5,29

Chapter 6 Class 12 Application of Derivatives

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.