Ex 6.5,6

Last updated at Dec. 8, 2016 by Teachoo

Ex 6.5, 6 - Find maximum profit that a company can make, p(x) - Ex 6.5

Transcript

Ex 6.5,6 Find the maximum profit that a company can make, if the profit function is given by 𝑝(𝑥) = 41 – 72𝑥 – 18𝑥2 The profit function is given by p(x) = 41 − 72x − 18x2 p’(x) = −72 − 36 x Putting p‘ (x) = 0 −72 − 36x = 0 −36x = 72 𝑥 =﷐−72﷮36﷯= −2 Now, P”(x) = −36 Since P” (x) < 0 𝑥=−2 is the maxima ∴ Maximum profit = p(−2) p(x) = 41 − 72x − 18x2 𝑝(−2)=41−72 ﷐−2﷯−18 ﷐﷐−2﷯﷮2﷯ =41+144−18 ﷐4﷯ =41+144−72 =113 Hence, the maximum profit is 113 unit.

Ex 6.5

Ex 6.5,6 You are here

Examples →

Chapter 6 Class 12 Application of Derivatives

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.

Manpreet Kaur

Feb. 17, 2018, 10:06 p.m.

Divide a number 15 in two parts such that the square of one multiplied by the cube of other is maximum.

View answer
Sharon Mallick

Sept. 17, 2017, 5:38 a.m.

Calculation on local maxima and minima

View answer