Subscribe to our Youtube Channel - https://you.tube/teachoo
Ex 6.5,9 - Chapter 6 Class 12 Application of Derivatives
Last updated at Jan. 7, 2020 by Teachoo
Transcript
Ex 6.5, 9 What is the maximum value of the function sinβ‘π₯+cosβ‘π₯? Let f(π₯)=sinβ‘π₯+cosβ‘π₯ Consider the interval π₯ β [0 , 2π] Finding fβ(π) fβ(π₯)=π(sinβ‘π₯ + cosβ‘π₯ )/ππ₯ fβ(π₯)=cosβ‘π₯βsinβ‘π₯ Putting fβ(π)=π cosβ‘π₯βsinβ‘π₯=0 cosβ‘π₯=sinβ‘π₯ 1 =sinβ‘π₯/cosβ‘π₯ 1= tanβ‘π₯ tan π₯=1 Since π₯ β [0 , 2π] tan π₯=1 at π₯=π/4 , π₯=5π/4 in the interval [0 , 2π] We have given the interval π₯ β [0 , 2π] Hence Calculating f(π₯) at π₯=0 ,π/4 , 5π/4 & 2π Hence Maximum Value of f(π₯) is βπ at π = π /π
Ex 6.5
Ex 6.5,1
Important
Ex 6.5,2 Important
Ex 6.5,3
Ex 6.5,4
Ex 6.5,5 Important
Ex 6.5,6
Ex 6.5,7 Important
Ex 6.5,8
Ex 6.5,9 Important You are here
Ex 6.5,10
Ex 6.5,11 Important
Ex 6.5,12 Important
Ex 6.5,13
Ex 6.5,14 Important
Ex 6.5,15 Important
Ex 6.5,16
Ex 6.5,17
Ex 6.5,18 Important
Ex 6.5,19 Important
Ex 6.5, 20 Important
Ex 6.5,21
Ex 6.5,22 Important
Ex 6.5,23 Important
Ex 6.5,24 Important
Ex 6.5,25 Important
Ex 6.5,26 Important
Ex 6.5, 27
Ex 6.5,28 Important
Ex 6.5,29
Chapter 6 Class 12 Application of Derivatives
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.