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Ex 6.5
Ex 6.5, 1 (ii)
Ex 6.5, 1 (iii) Important
Ex 6.5, 1 (iv)
Ex 6.5, 2 (i)
Ex 6.5, 2 (ii) Important
Ex 6.5, 2 (iii)
Ex 6.5, 2 (iv) Important
Ex 6.5, 2 (v) Important
Ex 6.5, 3 (i)
Ex 6.5, 3 (ii)
Ex 6.5, 3 (iii)
Ex 6.5, 3 (iv) Important
Ex 6.5, 3 (v)
Ex 6.5, 3 (vi)
Ex 6.5, 3 (vii) Important
Ex 6.5, 3 (viii)
Ex 6.5, 4 (i)
Ex 6.5, 4 (ii) Important
Ex 6.5, 4 (iii)
Ex 6.5, 5 (i)
Ex 6.5, 5 (ii)
Ex 6.5, 5 (iii) Important
Ex 6.5, 5 (iv)
Ex 6.5,6
Ex 6.5,7 Important
Ex 6.5,8
Ex 6.5,9 Important You are here
Ex 6.5,10
Ex 6.5,11 Important
Ex 6.5,12 Important
Ex 6.5,13
Ex 6.5,14 Important
Ex 6.5,15 Important
Ex 6.5,16
Ex 6.5,17
Ex 6.5,18 Important
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Ex 6.5, 20 Important
Ex 6.5,21
Ex 6.5,22 Important
Ex 6.5,23 Important
Ex 6.5,24 Important
Ex 6.5,25 Important
Ex 6.5,26 Important
Ex 6.5, 27 (MCQ)
Ex 6.5,28 (MCQ) Important
Ex 6.5,29 (MCQ)
Last updated at April 15, 2021 by Teachoo
Ex 6.5, 9 What is the maximum value of the function sinβ‘π₯+cosβ‘π₯? Let f(π₯)=sinβ‘π₯+cosβ‘π₯ Consider the interval π₯ β [0 , 2π] Finding fβ(π) fβ(π₯)=π(sinβ‘π₯ + cosβ‘π₯ )/ππ₯ fβ(π₯)=cosβ‘π₯βsinβ‘π₯ Putting fβ(π)=π cosβ‘π₯βsinβ‘π₯=0 cosβ‘π₯=sinβ‘π₯ 1 =sinβ‘π₯/cosβ‘π₯ 1= tanβ‘π₯ tan π₯=1 Since π₯ β [0 , 2π] tan π₯=1 at π₯=π/4 , π₯=5π/4 in the interval [0 , 2π] We have given the interval π₯ β [0 , 2π] Hence Calculating f(π₯) at π₯=0 ,π/4 , 5π/4 & 2π Hence Maximum Value of f(π₯) is βπ at π = π /π