Ex 6.3, 1 (iv) - Chapter 6 Class 12 Application of Derivatives
Last updated at August 12, 2026 by Teachoo
Ex 6.3
Ex 6.3, 1 (i)
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Chapter 6 Class 12 Application of Derivatives
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Transcript
Ex 6.3,1 (Method 1) Find the maximum and minimum values, if any, of the following functions given by (iv) f(š„) = š„3 + 1f(š„)=š„^3+1 Finding fā(x) fā(š„)=š(š„^3 + 1)/šš„ =3š„^2 Putting fā(š)=š 3š„^2=0 š„^2=0 š„=0 Therefore by first derivate test, the point š„=0 is neither a point of local maxima nor a point of local Minima Hence š=š is point of inflexion Hence, there is no minimum or maximum value Ex 6.3, 1 (Method 2) Find the maximum and minimum values, if any, of the following functions given by (iv) f(š„) = š„3 + 1f(š„)=š„^3+1 Finding fā(x) fā(š„)=š(š„^3+1)/šš„ =3š„^2 Putting fā(š)=š 3š„^2=0 š„^2=0 š„=0 Finding fāā(x) fā(x) = 3x2 fāā(x) = 6x Finding fāā(x) at x = 0 fāā(0) = 6 Ć 0 = 0 Since fāā(x) = 0 at x = 0 ā“ The point š„=0 is neither a point of local maxima nor a point of local Minima Hence š=š is point of inflexion Hence, there is no minimum or maximum value
