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Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 6.5
Ex 6.5, 1 (ii)
Ex 6.5, 1 (iii) Important
Ex 6.5, 1 (iv) You are here
Ex 6.5, 2 (i)
Ex 6.5, 2 (ii) Important
Ex 6.5, 2 (iii)
Ex 6.5, 2 (iv) Important
Ex 6.5, 2 (v) Important
Ex 6.5, 3 (i)
Ex 6.5, 3 (ii)
Ex 6.5, 3 (iii)
Ex 6.5, 3 (iv) Important
Ex 6.5, 3 (v)
Ex 6.5, 3 (vi)
Ex 6.5, 3 (vii) Important
Ex 6.5, 3 (viii)
Ex 6.5, 4 (i)
Ex 6.5, 4 (ii) Important
Ex 6.5, 4 (iii)
Ex 6.5, 5 (i)
Ex 6.5, 5 (ii)
Ex 6.5, 5 (iii) Important
Ex 6.5, 5 (iv)
Ex 6.5,6
Ex 6.5,7 Important
Ex 6.5,8
Ex 6.5,9 Important
Ex 6.5,10
Ex 6.5,11 Important
Ex 6.5,12 Important
Ex 6.5,13
Ex 6.5,14 Important
Ex 6.5,15 Important
Ex 6.5,16
Ex 6.5,17
Ex 6.5,18 Important
Ex 6.5,19 Important
Ex 6.5, 20 Important
Ex 6.5,21
Ex 6.5,22 Important
Ex 6.5,23 Important
Ex 6.5,24 Important
Ex 6.5,25 Important
Ex 6.5, 26 Important
Ex 6.5, 27 (MCQ)
Ex 6.5,28 (MCQ) Important
Ex 6.5,29 (MCQ)
Last updated at Aug. 19, 2021 by Teachoo
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Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 6.5,1 (Method 1) Find the maximum and minimum values, if any, of the following functions given by (iv) f(π₯) = π₯3 + 1f(π₯)=π₯^3+1 Finding fβ(x) fβ(π₯)=π(π₯^3 + 1)/ππ₯ =3π₯^2 Putting fβ(π)=π 3π₯^2=0 π₯^2=0 π₯=0 Therefore by first derivate test, the point π₯=0 is neither a point of local maxima nor a point of local Minima Hence π=π is point of inflexion Hence, there is no minimum or maximum value Ex 6.5, 1 (Method 2) Find the maximum and minimum values, if any, of the following functions given by (iv) f(π₯) = π₯3 + 1 π₯=0 Finding fββ(x) fβ(x) = 3x2 fββ(x) = 6x Finding fββ(x) at x = 0 fββ(0) = 6 Γ 0 = 0 Since fββ(x) = 0 at x = 0 β΄ The point π₯=0 is neither a point of local maxima nor a point of local Minima Hence π=π is point of inflexion Hence, there is no minimum or maximum value