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Example 1 - Chapter 6 Class 12 Application of Derivatives
Last updated at Jan. 7, 2020 by Teachoo
Transcript
Example 1 Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm. We have to find rate of change of area of circle with respect to radius i.e. we need to find (๐(๐ด๐๐๐ ๐๐ ๐๐๐๐๐๐))/(๐ (๐๐๐๐๐ข๐ ๐๐ ๐๐๐๐๐๐)) = ๐๐ด/๐๐ We know that Area of circle = ฯ r2 A = ฯr2 Finding ๐๐ด/๐๐ ๐๐ด/๐๐ = (๐(๐๐2))/๐๐ = ฯ ((๐2))/๐๐ = ฯ (2r) = 2ฯ r For r = 5 cm ๐๐ด/๐๐ = 2ฯ (5) . ๐๐2/๐๐ = 10ฯ ๐๐๐/๐๐ As dimension of area is cm2 & dimension of Radius is cm
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Example 42 Important Not in Syllabus - CBSE Exams 2021
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Example 49 Not in Syllabus - CBSE Exams 2021
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Chapter 6 Class 12 Application of Derivatives
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.