Check sibling questions

Examples

MiscellaneousΒ β†’
Chapter 6 Class 12 Application of Derivatives
Serial order wise

Example 1 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2023 by

Example 1 - Find rate of change of area of circle per second

Example 1 - Chapter 6 Class 12 Application of Derivatives - Part 2

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Book a free demo

Transcript

Example 1 Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm.We have to find rate of change of area of circle with respect to radius i.e. we need to find (𝒅(𝑨𝒓𝒆𝒂 𝒐𝒇 π’„π’Šπ’“π’„π’π’†))/(𝒅 (π’“π’‚π’…π’Šπ’–π’” 𝒐𝒇 π’„π’Šπ’“π’„π’π’†)) = 𝒅𝑨/𝒅𝒓 We know that Area of circle = Ο€ r2 A = Ο€r2 Finding 𝒅𝑨/𝒅𝒓 𝑑𝐴/π‘‘π‘Ÿ = (𝑑(πœ‹π‘Ÿ2))/π‘‘π‘Ÿ = Ο€ ((π‘Ÿ2))/π‘‘π‘Ÿ = Ο€ (2r) = 2Ο€r For r = 5 cm 𝑑𝐴/π‘‘π‘Ÿ = 2Ο€ (5) = 10Ο€ cmx/s

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.