Example 1 - Chapter 6 Class 12 Application of Derivatives
Last updated at May 29, 2018 by Teachoo
Transcript
Example 1 Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm. We have to find rate of change of area of circle with respect to radius i.e. we need to find ๏ท๐(๐ด๐๐๐ ๐๐ ๐๐๐๐๐๐)๏ทฎ๐ (๐๐๐๐๐ข๐ ๐๐ ๐๐๐๐๐๐)๏ทฏ = ๏ท๐๐ด๏ทฎ๐๐๏ทฏ We know that Area of circle = ฯ r2 A = ฯr2 Finding ๏ท๐๐ด๏ทฎ๐๐๏ทฏ ๏ท๐๐ด๏ทฎ๐๐๏ทฏ = ๏ท๐(๐๐2)๏ทฎ๐๐๏ทฏ = ฯ ๏ท(๐2)๏ทฎ๐๐๏ทฏ = ฯ (2 . r2 โ1) = 2ฯ r For r = 5 cm ๏ท๐๐ด๏ทฎ๐๐๏ทฏ = 2ฯ (5) . ๏ท๐๐2๏ทฎ๐๐๏ทฏ = 10ฯ ๏ท๐๐๐๏ทฎ๐๐๏ทฏ
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Chapter 6 Class 12 Application of Derivatives
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.