Example 1 - Chapter 6 Class 12 Application of Derivatives (Term 1)
Last updated at May 6, 2021 by Teachoo
Examples
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Transcript
Example 1 Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm.We have to find rate of change of area of circle with respect to radius i.e. we need to find (π (π¨πππ ππ ππππππ))/(π (πππ πππ ππ ππππππ)) = π π¨/π π We know that Area of circle = Ο r2 A = Οr2 Finding π π¨/π π ππ΄/ππ = (π(ππ2))/ππ = Ο ((π2))/ππ = Ο (2r) = 2Οr For r = 5 cm ππ΄/ππ = 2Ο (5) = 10Ο cmx/s
