Example 1 - Chapter 6 Class 12 Application of Derivatives (Term 1)
Last updated at May 6, 2021 by Teachoo
Transcript
Example 1 Find the rate of change of the area of a circle per second with respect to its radius r when r = 5 cm.We have to find rate of change of area of circle with respect to radius i.e. we need to find (๐ (๐จ๐๐๐ ๐๐ ๐๐๐๐๐๐))/(๐ (๐๐๐ ๐๐๐ ๐๐ ๐๐๐๐๐๐)) = ๐ ๐จ/๐ ๐ We know that Area of circle = ฯ r2 A = ฯr2 Finding ๐ ๐จ/๐ ๐ ๐๐ด/๐๐ = (๐(๐๐2))/๐๐ = ฯ ((๐2))/๐๐ = ฯ (2r) = 2ฯr For r = 5 cm ๐๐ด/๐๐ = 2ฯ (5) = 10ฯ cmx/s
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.