# Example 21 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 21 Use differential to approximate 36.6 Let y = Let x = 36 & x = 0.6 Since y = = ( ) = 1 2 Now, = x = 1 2 (0.6) = 1 2 36 (0.6) = 0.6 2 6 = 0.05 Also, = + Putting values 0.05= 36+0.6 36 36.6 =0.05+ 36 36.6 =0.05+6 = + x 36.6 = 6.05 Hence, approximate value of 36.6 is 6.05

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Example 21 You are here

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Chapter 6 Class 12 Application of Derivatives

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.