Subscribe to our Youtube Channel - https://you.tube/teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 20 Find the equation of tangent to the curve given by x = a sin3 t , y = b cos3 t at a point where t = 𝜋2 . The curve is given as x = a sin3t y = b cos3t Slope of the tangent = 𝑑𝑦𝑑𝑥 𝑑𝑦𝑑𝑥 = 𝑑𝑦𝑑𝑡𝑑𝑥𝑑𝑡 Hence 𝑑𝑦𝑑𝑥 = −3𝑏𝑐𝑜𝑠2𝑡sin𝑡3𝑎sin2𝑡cos𝑡 = −𝑏cos𝑡𝑎sin𝑡 Now, Slope of the tangent at t = 𝜋2 is 𝑑𝑦𝑑𝑥𝑡 = 𝜋 2 = −𝑏cos 𝜋2𝑎sin 𝜋2 = −𝑏(0)𝑎(1) = 0 Also at t = 𝜋2, value of x and y is Hence, point is (a, 0) Hence, the equation of the tangent at point (𝑎, 0) and with slope 0 is y − 0 = 0 (x − 𝑎) y = 0

Examples

Example 1

Example 2

Example 3

Example 4 Important

Example 5

Example 6

Example 7

Example 8 Important

Example 9 Important

Example 10

Example 11 Important

Example 12

Example 13 Important

Example 14

Example 15

Example 16

Example 17 Important

Example 18

Example 19

Example 20 You are here

Example 21

Example 22

Example 23

Example 24

Example 25

Example 26

Example 27

Example 28 Important

Example 29

Example 30 Important

Example 31

Example 32 Important

Example 33 Important

Example 34

Example 35 Important

Example 36

Example 37 Important

Example 38 Important

Example 39

Example 40 Important

Example 41 Important

Example 42 Important

Example 43 Important

Example 44 Important

Example 45 Important

Example 46 Important

Example 47 Important

Example 48 Important

Example 49

Example 50 Important

Example 51

Chapter 6 Class 12 Application of Derivatives

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.