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Last updated at April 19, 2021 by Teachoo

Example 25 If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximate error in calculating its volume.Given Radius of sphere = r = 9 cm Error in radius = βr = 0.03 cm We need to find Error in calculating Volume Let Volume of sphere = V = π/π π π^π β΄ We need to find βV Now, βV = ππ/ππ βr = π(4/3 ππ^3 )/ππ βr = 4/3 π (ππ^3)/ππ βr = 4/3 π (3π^2 )(0.03 ) = 4ππ^2(0.03) = 4π(9)2 (0.03) = 9.72π cm3 Hence, approximate error in calculating volume is 9.72π cm3