Examples
Last updated at December 16, 2024 by Teachoo
Transcript
Question 10 Find the approximate value of f (3.02), where f (x) = 3x2 + 5x + 3.Given f(x) = 3x2 + 5x + 3 where x = 3 and āš„=0.02 Finding fā(x) fā(x) = 6x + 5 Now, ā³y = fā(x) āš = (6x + 5) 0.02 Putting x = 3 = (6 Ć 3 + 5) 0.02 = 23 Ć 0.02 = 0.46 Now, f(x + āš) = f(x) + āš f(3.02) = f(3) + 0.46 = (3 Ć 32 + 5 Ć 3 + 3) + 0.46 = (27 + 15 + 3) + 0.46 = 45 + 0.46 = 45.46 Hence, approximate value of f(3.02) is 45.46