# Example 23 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 23 Find the approximate value of f (3.02), where f (x) = 3x2 + 5x + 3. Let x = 3 and âđ„=0.02 Given f(x) = 3x2 + 5x + 3 fâ(x) = 6x + 5 Now, âły = fâ(x) âđ„ = (6x + 5) 0.02 Also, âđŠ = f(x + âđ„) â f(x) f (x + âđ„) = f(x) + âđŠ f (3.02) = (3x2 + 5x + 3) + (6x + 5) 0.02 Putting value of x, âđ„ & âđŠ f (3.02) = ï·3ï·ï·3ï·Żï·ź2ï·Ż5ï·3ï·Ż+3ï·Ż+ï·6ï·3ï·Ż+5ï·Ż0.02 = (27 + 15 + 3) + (23) 0.02 = 45 + 0.46 = 45.46 Hence, approximate value of f (3.02) is 45.46

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Chapter 6 Class 12 Application of Derivatives

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.