



Last updated at May 29, 2018 by Teachoo
Transcript
Example 51 Manufacturer can sell items at a price of rupees 5 100 each. The cost price of items is Rs 5 +500 Find the number of items he should sell to earn maximum profit. Let S be the selling price of items. & C be the cost price of item. Given Manufacture sell items at a price of rupees 5 100 each i.e. S = 5 100 = 5 2 100 Also given Cost of x items is Rs. 5 +500 i.e. C = 5 + 500 We need to maximize profit let P be the profit P = selling price cost price P = S C P = 5 2 100 5 +500 = 5 2 100 5 500 = 25 5 2 100 500 = 24 5 2 100 500 Hence, P = 24 5 2 100 500 Diff w.r.t x P = 24 5 2 100 500 P = 24 5 2 100 0 P = 24 5 50 Putting P = 0 24 5 50 = 0 50 = 24 5 = 24 5 50 = 240 Finding P P = 24 5 50 Diff w.r.t P = 24 5 50 = 0 1 50 = 1 50 Putting = 240 240 = 1 50 < 0 P < 0 at = 240 = 240 is point of maxima Thus, P is maximum when = 240 Hence the manufacturer can earn maximum profit if he sells 240 items.
Examples
Example 2
Example 3
Example 4
Example 5
Example 6
Example 7
Example 8
Example 9
Example 10
Example 11
Example 12
Example 13
Example 14
Example 15
Example 16
Example 17
Example 18
Example 19
Example 20
Example 21
Example 22
Example 23
Example 24
Example 25
Example 26
Example 27
Example 28
Example 29
Example 30
Example 31
Example 32
Example 33
Example 34
Example 35 Important
Example 36
Example 37 Important
Example 38 Important
Example 39
Example 40 Important
Example 41
Example 42
Example 43
Example 44
Example 45
Example 46 Important
Example 47 Important
Example 48
Example 49
Example 50
Example 51 You are here
About the Author