# Example 29 - Chapter 6 Class 12 Application of Derivatives

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 29 (Method 1) Find all points of local maxima and local minima of the function f given by ( ) = 3 3 + 3. ( )= 3 3 +3 Step 1: Finding ( ) = 3 2 3+0 = 3 2 1 Step 2: Putting = 0 3 2 1 =0 2 1=0 1 +1 =0 Thus = 1 , 1 are only critical points Step 3: Example 29(Method 2) Find all points of local maxima and local minima of the function f given by ( ) = 3 3 + 3. ( )= 3 3 +3 Step 1: Finding ( ) = 3 2 3+0 = 3 2 1 Step 2: Putting = 0 3 2 1 =0 2 1=0 1 +1 =0 So, x = 1 & x = 1 Step 3: Finding =3 2 1 =3 2 1 =3 2 0 =6 Finding maximum & minimum value of ( )= 3 3 +3 Minimum value (1)= 1 3 3 1 +3= 1 3 + 3 = 1 Maximum value ( 1)= 1 3 3 1 +3= 1 +3 + 3 = 5

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Chapter 6 Class 12 Application of Derivatives

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.