Last updated at April 19, 2021 by Teachoo

Transcript

Example 15 Find the point at which the tangent to the curve ๐ฆ = โ(4๐ฅโ3)โ1 has its slope 2/3 . Given, Slope of the tangent to the curve is 2/3 We know that Slope of tangent = ๐ ๐/๐ ๐ 2/3 = ๐๐ฆ/๐๐ฅ ๐๐ฆ/๐๐ฅ = 2/3 ๐(โ(4๐ฅ โ 3) โ 1)/๐๐ฅ = 2/3 1/(2โ(4๐ฅ โ 3)) ร4โ0 = 2/3 2/โ(4๐ฅ โ 3) = 2/3 3 = โ(4๐ฅโ3) โ(๐๐โ๐) = 3 Squaring both sides 4x โ 3 = 9 4x = 12 x = 3 Finding y for x = 3 ๐ฆ=โ(4๐ฅโ3) โ 1 =โ(12โ3)โ1 =โ9โ1 =3โ1 =๐ Hence, the required point is (๐, ๐)

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Chapter 6 Class 12 Application of Derivatives

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.