Example 18 - Chapter 6 Class 12 Application of Derivatives
Last updated at May 29, 2018 by Teachoo
Transcript
Example 18 Find the equation of the tangent to the curve y = 7 2 ( 3) at the point where it cuts the x-axis. Slope of the tangent to the curve is = 7 2 3 7 3 + 2 2 2 3 2 = 1 2 3 7 1 3 + 2 2 2 3 2 = 2 3 7 2 5 2 2 3 2 = 1 2 5 2 3 At the point where the curve cuts the x axis, y = 0 Hence the equation of the curve is 0 = 7 2 3 x = 7 The curve cuts the x axis at point (7, 0) At point (7, 0) the slope is 7, 0 = 1 0 2 7 5 7 2 7 3 = 1 5 4 = 1 20 Now, the equation of the tangent at point (7, 0) with slope 1 20 is 1 = 1 0= 1 20 7 20 = 7 + =
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Chapter 6 Class 12 Application of Derivatives
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.