Ex 6.2, 1 - Show that f(x) = 3x + 17 is strictly increasing - To show increasing/decreasing in whole domain

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  1. Chapter 6 Class 12 Application of Derivatives
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Ex 6.2,1(Method 1) Show that the function given by f ( ) = 3 + 17 is strictly increasing on R. f( ) = 3 + 17 f ( ) = 3 value of f ( ) is positive for all real number Hence f ( ) = positive for all R f is strictly increasing on R Ex 6.2,1(Method 2) Show that the function given by f (x) = 3x + 17 is strictly increasing on R. Let 1 and 2 be real numbers Such that 1 < 2 Multiplying both sides by 3 3 1 < 3 2 Adding both sides by 3 3 1 + 17 < 3 2 + 17 f ( 1) < f ( 2) Hence if 1 < 2 Then f ( 1) < f ( 2) Hence f is strictly increasing on R

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.