Ex 6.2, 1 Class 12 - Show that f(x) = 3x + 17 is strictly increasing

Ex 6.2, 1 - Chapter 6 Class 12 Application of Derivatives - Part 2

  1. Chapter 6 Class 12 Application of Derivatives (Term 1)
  2. Serial order wise

Transcript

Ex 6.2, 1 (Method 1) Show that the function given by f (๐‘ฅ) = 3๐‘ฅ + 17 is strictly increasing on R. f(๐‘ฅ) = 3๐‘ฅ + 17 Finding fโ€™(๐’™) fโ€™(๐‘ฅ) = 3 Since fโ€™(๐’™) > 0 Hence, f is strictly increasing on R Ex 6.2, 1 (Method 2) Show that the function given by f (x) = 3x + 17 is strictly increasing on R. Let ๐‘ฅ1 and ๐‘ฅ2 be real numbers Such that ๐’™๐Ÿ < ๐’™2 Multiplying both sides by 3 3๐‘ฅ1 < 3 ๐‘ฅ2 Adding both sides by 17 3๐‘ฅ1 + 17 < 3๐‘ฅ2 + 17 f (๐’™๐Ÿ) < f ( ๐’™2) Hence, when x1 < x2 , f(x1) < f(x2) Thus, f(x) is strictly increasing on R.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.