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Ex 6.2, 15 - Let I be any interval disjoint from [–1, 1]. Prove

Ex 6.2,15 - Chapter 6 Class 12 Application of Derivatives - Part 2
Ex 6.2,15 - Chapter 6 Class 12 Application of Derivatives - Part 3

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Transcript

Ex 6.2, 15 Let I be any interval disjoint from [–1, 1]. Prove that the function f given by 𝑓(𝑥) = 𝑥 + 1/𝑥 is strictly increasing on I.I is any interval disjoint from [–1, 1] Let I = (−∞, −𝟏)∪(𝟏, ∞) Given f(𝑥) = 𝑥 + 1/𝑥 We need to show f(𝑥) is strictly increasing on I i.e. we need to show f’(𝒙) > 0 for 𝑥 ∈ (−∞, −𝟏)∪(𝟏, ∞) Finding f’(𝒙) f(𝑥) = 𝑥 + 1/𝑥 f’(𝑥) = 1 – 1/𝑥2 f’(𝑥) = (𝑥2 − 1)/𝑥2 Putting f’(𝒙) = 0 (𝑥2 − 1)/𝑥2 = 0 𝑥2−1 = 0 (𝑥−1)(𝑥+1)=0 So, 𝒙=𝟏 & 𝒙=−𝟏 Plotting points on number line The point 𝑥 = –1 , 1 into three disjoint intervals ∴ f(x) is strictly increasing on (−∞ , −𝟏) & (𝟏 , ∞) Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.